Suppressing pushd output

[Tony van der Hoff <tony@vanderhoff.org>]

Hi,

In my shell (bash) scripts, I occasionally use pushd/popd to descend
into subdirectories;

pushd $dir; do_something; popd

Unfortunately the pushd/popd generate a lot of (mostly) unwanted output,
with no apparent way of suppressing it.
So, my solution is:

pushd $dir >/dev/null; do_something; popd >/dev/null

which has the desired effect, but for debugging, it's useful to
re-enable the output.

I tried, and failed, this:

DEBUG=1
if [ $DEBUG -eq 0 ]; then
	NULLOUT='>/dev/null'
fi
pushd $dir ${NULLOUT}; do_something; popd ${NULLOUT}

The $NULLOUT is totally ineffective.

Any suggestions as to why this might be so?

-- 
Tony van der Hoff  | mailto:tony@vanderhoff.org
Ariège, France     |