Re: How to pass variable to wget ?

["J. Bakshi" <bakshi12@gmail.com>]

On Sun, 22 Jan 2012 12:43:55 +0100
Sven Joachim <svenjoac@gmx.de> wrote:

> On 2012-01-22 12:27 +0100, J. Bakshi wrote:
> 
> > I have a script which submits a form with wget --post-data
> >
> > [....]
> >
> > #!/bin/bash
> >
> > Uname=xyz
> > Pword=1234
> >
> > wget -O - --save-cookies cookies.txt --post-data \
> > 'username=$Uname&password=$Pword'  --keep-session-cookies $URL/$AUTHURL   1&>2
> >
> > [....]
> >
> > During the test with "bash -x" I see the variables are not evaluated and they appear as
> > $Uname and $Pword. But if I put an echo for testing at top like
> >
> > echo $Uname
> >
> > the value is evaluated correctly.
> > Am I missing something ?
> 
> Yes, the single quotes in your wget command which prevent bash from
> expanding the variables.  Use double quotes instead, see
> http://www.gnu.org/software/bash/manual/bashref.html#Quoting.
> 
> Sven
> 
Working nicely...

Thanks :-)