Re: how to check 400 files exist

[Anand Sivaram <aspnair@gmail.com>]

2012/1/19 lina <lina.lastname@gmail.com>

On Thu, Jan 19, 2012 at 1:35 AM, Wawrzek Niewodniczanski
<wawrzek.niewodniczanski@citrix.com> wrote:
> On 01/18/12 16:34, lina wrote:
>
> Hi,
>
> Thanks ahead for reading this email.
>
> I am choked by how to check more than 400 files exist or not, if not,
> sleep, but once it's all generated, continue do something.
>
> for i in $(seq 5); do if [ -e sys_em_$i.txt ] ; then echo done ; fi ;
> done not work.
>
> those files have a common feature:
>
> sys_em_$i.txt
>
> What about  using `ls -1  sys_em_*.txt | wc -l` to check the number of
> files.
>
> I.e. (I hope it works):
>
> my_number = 400
> while :
> do
>   if  [ ` ls -1  sys_em_*.txt | wc -l` == "$my_number" ] then

Thanks,
but here it complains so many $ ./check_file.sh
./check_file.sh: line 8: [: too many arguments

>     break
>   sleep 5
>   fi
> done
>
> Thanks,
> Wawrzek
> --
> Wawrzyniec (Wawrzek) Niewodniczański - (niewod @ LinkedIn)
> System Administrator - Engineering Services Team (XenServer)
> Citrix Systems, Building 101, Cambridge Science Park, CB4 0FY, Cambridge
> PhD in Quantum Chemistry, MSc in Molecular EngineeringM

--
To UNSUBSCRIBE, email to debian-user-REQUEST@lists.debian.org
with a subject of "unsubscribe". Trouble? Contact listmaster@lists.debian.org

Archive: http://lists.debian.org/CAG9cJmmooL1FAqac6RRGSJE74bW0Uv2Nbp79DGz6J6ELJpVFA@mail.gmail.com

How about this
m=0; # missing
n=0; #not missing
for ((k=0;k<400;k++))
do
  if [ -e sys_em_$k.txt ] 
  then
    n=$(expr $n + 1)
  else
    m=$(expr $m + 1)
  fi
done

echo "missing = " $m
echo "not missing = " $n


-- 
http://saurorja.org
Twitter: @anand_sivaram