Re: Bash question: get output as a variable?

[Mart Frauenlob <mart.frauenlob@chello.at>]

On 05.02.2010 09:07, Ken Teague wrote:
> On Thu, Feb 4, 2010 at 2:09 PM, Dotan Cohen <dotancohen@gmail.com> wrote:
>> I'm scripting a backup solution, the line that does the business looks
>> like this:
>>
>> tar -zcvf - *  --exclude-from $EXCLUDES  | openssl des3 -salt -k $1 |
>> dd of=$(hostname)-$(date +%Y%m%d).tbz
>>
>> Because of the "v" flag tar writes to stdout the name of each file
>> copied. How can I get that output redirected to a variable, to use
>> later in the script?
> 
> You probably want to put the data into an array rather than a
> variable.  An explanation of how to do so can be found here:
>  http://tldp.org/LDP/abs/html/arrays.html
> 
> #!/bin/bash

tar ... 2> "$filename"
mapfile array1 < "$filename"

(don't know actually why '-u 2' option for mapfile does not complete for
me? would make it a 'one-liner'.)

on bash4.0+

regards

Mart