Re: Bash question: get output as a variable?
On Fri, Feb 5, 2010 at 10:10 AM, Chris Jackson
> Use $() like you do with the date command. You have to redirect stderr back
> to stdout, which means running it in a subshell:
> FILES=$( ( tar -zcvf - * --exclude-from $EXCLUDES | openssl des3 -salt -k
> $1 | dd of=$(hostname)-$(date +%Y%m%d).tbz ) 2>&1 )
> It may cause unexpected results if there're spaces in the filenames though.
I think this is the best method I've seen thus far. Putting the data
into an array should avoid problems with file names containing spaces.
I don't understand why he would stderr in it, though. I'd like to
know what the OP plans to do with the list of processed files.