Re: Use of Swap Space
- To: debian-user@lists.debian.org
- Subject: Re: Use of Swap Space
- From: Ron Johnson <ron.l.johnson@cox.net>
- Date: Sat, 31 Jan 2009 23:18:22 -0600
- Message-id: <[🔎] 4985309E.5060501@cox.net>
- In-reply-to: <6b1504c40901311327q37eb6d26g3acdb23e6b45f56b@mail.gmail.com>
- References: <f28eb7fc0901301654x2e802b37n821f391ee97465c4@mail.gmail.com> <jwv1vujb4gc.fsf-monnier+gmane.linux.debian.user@gnu.org> <6b1504c40901311327q37eb6d26g3acdb23e6b45f56b@mail.gmail.com>
On 01/31/2009 03:27 PM, Nuno Magalhães wrote:
Try to run `free' to get a more detailed break up (or even "cat
/proc/meminfo").
Running free -g on my system returns 3. I have 4.
Running cat /proc/meminfo returns 4030668KB, which is 3.84GB according
That's 4030668*1024 = 4,127,404,032.
to onlineconversion, closer. Does RAM also have a sort of FAT?
4GB = 4,294,967,296.
So, where's the missing 167,563,264 bytes? (I.e. 40,909 4KB pages.)
It seems as though free won't return the accurate size.
Of course it does. "We", though, aren't kernel hackers or h/w
gurus, so are left in the dark.
--
Ron Johnson, Jr.
Jefferson LA USA
"I am not surprised, for we live long and are celebrated poopers."
Reply to: