On Fri, Sep 5, 2008 at 8:00 AM, David Parker <dparker@utica.edu
<mailto:dparker@utica.edu>> wrote:
----- Original Message -----
From: "L.V.Gandhi" <lvgandhi@gmail.com <mailto:lvgandhi@gmail.com>>
Date: Thursday, September 4, 2008 9:50 pm
Subject: error in script
To: debian-user <debian-user@lists.debian.org
<mailto:debian-user@lists.debian.org>>
> I have a script as follows
> #!/bin/bash
> rm -f ~/stock/flstock.csv
> grep FUTSTK ~/stock/today/$1 |grep "25/09/2008"|cut -s -d,
-f9|sort -nr > temp
> i=0
> for trv in $(cat temp)
> do
> grep $trv ~/stock/today/$1 >> ~/stock/flstock.csv
> i=$((i+1))
> if [ $i -eq 20 ]
> then
> exit 0
> fi
> done
> rm -f temp
> cat ~/stock/flstock.csv |cut -s -d, -f2|sort >>
~/stock/fliquidstocks.txt
> Last line is not getting executed . But if I run last line
afterwards in console, it works.
> Can someone throw somelight why it happens.
Try echoing the value of $i each time through the loop. I wonder if
the "exit 0" when $i = 0 is the problem.
- Dave
Thanks. I think you are correct. What should do to come out of loop
instead of exiting the script.