Vá: Vá: awk FIELDWIDTHS howto?

["Paul Csanyi" <csanyipal@gmail.com>]

2008/1/9, Sergio Cuéllar Valdés <herrsergio@gmail.com>:
> 2008/1/9, Paul Csanyi <csanyipal@gmail.com>:
> > 2008/1/9, Sergio Cuéllar Valdés <herrsergio@gmail.com>:
> > > 2008/1/9, Paul Csanyi <csanyipal@gmail.com>:
> >
> > > > I try to use awk to print second field from a text file
> > > > but awk prints a part of 1. field as a 2. field. Why?
> > > >
> > > > aptitude search ~i | awk '{ NF = "2" } { FIELDWIDTHS = " 4 32 " }
> > > > {print $2}' > foltelepitett_debian_csomagok
> > > >
> > > > less foltelepitett_debian_csomagok
> > > >
> > > > ..
> > > > bsdmainutils
> > > > bsdutils
> > > > busybox
> > > > A
> > > > ca-certificates
> > > > checksecurity
> >
> > A record is like these:
> >
> > i busybox - Tiny utilities for small and embedded syst
> > i A bzip2 - high-quality block-sorting file compressor
> >     |
> > 1234123456789etc.
> > 1.  |2.
> >
> > I try to get only the package name from the 2. field.
> >
> > FIELDWIDTHS = " 4 32 "
> >
> > The given width for 1. field (4) should be right, but isn't.
> > Awk give me the letter "A" as a 2. field. Why?

> So, if you only need package name:
>
>  aptitude search ~i | cut -d" " -f3

It is cut, not awk.
Howewer, it is not god. The output file contains empty lines
besides of the package names.

-- 
Regards, Paul Csanyi
http://www.freewebs.com/csanyi-pal/index.htm