Re: using sizeof
On Mon, 14 May 2007 16:24:59 +0000, J HU wrote:
> Dear all,
>
> Perhaps it's an easy/silly question but I don't understand how it works.
>
> (I'm working in a debian)
> I have declared a structure and I'm using the "sizeof" to get the size of
> this structure.
>
> After the call I get that the total size is 64Bytes but if I get the size of
> each field and I add them manually I get that it should be 61Bytes...
>
> Anyone knows why the result is not the same?
>
> Thanks in advance
>
> Javi
>
Because sizeof is not really the size of the struct, it is the distance
between adjacent structs in an array. Alignment forces the extra bytes.
In my opinion, 'sizeof' should have been called 'spacingof', and there
should have been other properties for alignment, such as sizeof,
modulusof. and remainderof, so you could do your own storage
allocation calculations in a machine-independent way.
Something could take sizeof bytes starting at an address that is
remainderof bytes past a n address that is a multiple of modulusof.
The log2 of modulus would also be useful.
-- hendrik
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