Printing the date just before execution of commands in bash
Hi all. I'm wondering if anyone knows how I might be able to execute
the same command just before the execution of a command issued at the
prompt of a bash shell.
Currently, I have my bash prompt set up so that it displays the current
date. If I can print the date just before each command is executed, I
can always be able to get a sense of how long each command has taken.
Anyone has any idea how I might go about printing the date just before
the execution of each bash command? I just don't know where I would
start. Thanks for any help.
--
Sincerely
Jose Alburquerque
Reply to: