Re: amd64: why is sizeof(int) =4? why not =8?

[Mitchell Laks <mlaks@verizon.net>]

On Wednesday 05 April 2006 09:45, Ron Johnson wrote:
> On Wed, 2006-04-05 at 06:48 -0500, Mitchell Laks wrote:
> > Hi,
> >
> > I wanted to find out more about amd64, so I installed the debian distro

Yes, I installed the debian amd64 distro.

 (I thought that was clear :) I wanted to find out more about amd64 so I 
installed the debian (amd64) distro. Why would I install the  i386 one to 
find out about amd64? I already have 20 Sarge as well as Sid  installs on 
386!)
>
> Did you install the 64 bit version?
>
> > (etch/sid) on my amd64 dual core system.
>
>    ^^^^^^^^
>
> Which one?  Etch or Sid?

I installed using the etch Beta installer disk and immediately upgraded to sid 
(Like I usually do for workstations - Hey I like to live dangerously!). 

However I notice that system tty on boot up says

Debian Gnu/Linux testing/unstable Rashi tty4

Thats why I wrote that.  

Now that you make your comment, why does it say testing/unstable in the 
tty1-6 on all my sid machines? 

After all, I am running sid.  I do have both sid and testing in 
the /etc/apt/sources.lst file but I use no pinning, and want unadulterated 
sid... 


> AMD decided that, to help with compatibility with s/w written when
> sloppy programmers assumed that sizeof(int) == sizeof(*), integers
> will be 32 bits, even in 64 bit mode.

Thank You !!!!!!!!!!!!! Now I see indeed! when i do 

int * pointer;
intf("Size of int  * is %d\n",sizeof(pointer ));

indeed it does print out 8 !!!


Thanks. You also answered my question on how to program to 64 bit. I just use 
int64 ie long long. Thanks!!! 

Mitchell