Re: bash question: reporting a variable named within a variable
On Fri, Apr 04, 2003 at 12:34:33AM +0100, Colin Watson wrote:
> On Thu, Apr 03, 2003 at 01:58:35PM -0800, Corey Hickey wrote:
> > #!/bin/bash
> >
> > FOO=bar
> > BLAH=blarg
> >
> > for var in FOO BLAH ; do
> > echo $var = $"$var" #this part is messed up
> > done
>
> Try this, which I believe to be the best way:
>
> echo '$var = ' `eval 'echo "$foo"'`
Make that:
echo "$var = " `eval 'echo "$foo"'`
--
Colin Watson [cjwatson@flatline.org.uk]
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