Re: adding multiple users, newuser? and vim
On Sun, Aug 26, 2001 at 02:15:38PM -0700, Osamu Aoki wrote:
> Took me a while to get this working. Not bad excersize reading "Lerning
> Python". Does any one have suggestions of better python coding practice?
for real advice you should try the python mailing list. But for starters:
don't use tabs for indentation, use 4 explicit space. Besides I lost the
original postings, so I can't check whether this does what was asked for.
> #! /usr/bin/env python
> import sys, string
> # (C) Osmu Aoki Sun Aug 26 16:53:55 UTC 2001 Public Domain
> # Ported from awk script by KMSelf Sat Aug 25 20:47:38 PDT 2001
> # This program is distributed WITHOUT ANY WARRANTY.
> def usages():
> print \
Python has triple quoted multi line strings and fprint functionality,
so this could become:
print """Usage: %s start_UID [filename]
startUID is the starting userid to add.
filename is input file name. If not specified, standard input.
Input file format:
tfirstname lastname password""" % sys.argv
> return 1
there is no need for this return statement
> def parsefile(startuid):
> # main filtering
> uid = startuid
> while 1:
> line = infile.readline()
> if not line:
> (first, last, passwd) = string.split(string.lower(line))
no need to enclose those in (), remember the comma is the tuple maker.
> # above crash with wrong # of parameters :-)
> user = first + last
> gid = uid
> lineout = "%s:%s:%d:%d:%s %s,,/home/%s:/bin/bash\n" % \
> (user, passwd, uid, gid, first, last, user)
I doubt this does what you think it does, better try:
uid = uid + 1
> if __name__ == '__main__':
> if len(sys.argv) == 1:
> uid = int(sys.argv)
> #print "# UID start from: %d\n" % uid
> if len(sys.argv) > 1:
> infilename = string.join(sys.argv[2:])
I don't get what join was ment to do here
> infile = open(infilename, 'r')
> #print "# Read file from: %s\n\n" % infilename
> infile = sys.stdin