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Re: [OT] Perl: exec and $variables



On Sat, Jul 21, 2001 at 01:46:25PM +0200, Joost Kooij wrote:
> On Sat, Jul 21, 2001 at 01:04:40PM +0200, Sven Burgener wrote:
> > my $BEGINREGEX   = "sprintf(\"^<!-- // begin of news\$no // !-->\$\")";
> 
> Please tell us what you're trying to accomplish first.  It is unclear
> what assumptions you are making.

What I want is the variable $BEGINREGEX to contain a string like so:

^<!-- // begin of news1 // !-->$

or

^<!-- // begin of news2 // !-->$

The digit after the "news" should be whatever $no is set to at that
point in the script.

> > my $no = 1;
> > my $bla = eval($BEGINREGEX);
> > print "$bla\n";
> > 
> > $bla is empty for some reason.
> 
> You probably do not want to use eval here, or at least not in this way.

What should I do then?

It's simple, really. I am sure I am just making a stupid mistake.

my $BEGINREGEX = "sprintf(\"^<!-- // begin of news\$no // !-->\$\")";
my $no = 99;
my $bla = eval($BEGINREGEX);
print "regex string: $bla\n";

What should be printed:

regex string: ^<!-- // begin of news99 // !-->$


But it isn't, so what am I doing wrong here?

Cheers,
Sven
-- 
The best way to escape from a problem is to solve it. 



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