Re: OT: regular expression question
Viktor Rosenfeld scripsit:
>Frodo Baggins wrote:
>
>> [Pumping Lemma]
>
>> 1 w = xyz
>> 2 y is not empty
>> 3 x has less than n caracters
>
>That would be xy has less than/equal to n characters (|xy| <= n).
>
>> 4 for any integer k, the word w_k = xyy..yz (k times y) is in the
>> language (i.e. matches the regex)
Yes, you're right... It was late at night and I was a bit tired:)))))
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Leo TheHobbit
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GED/CS d? s-:+>-: a C+++ U+++ L++(+++)>++++ P+++>+++++ E+(++)
W++ N+ K? o? !w O? M V--- PS+++ PE-- Y+ GPG+ t++ 5? X- R+ tv+
b++++ D? DI? G e(++++)* h(+) r--(---) y--(+)>+++*
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