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Re: compiling kernel



When Hamish Moffatt wrote, I replied:

I've encountered a puzzling problem during kernel compilation that I
hope
some one can elucidate for me.  My make-kpkg buildpackage run ends with:

 signfile kernel-source-2.2.1_1.0.dsc
Pretty Good Privacy(tm) 2.6.3a - Public-key encryption for the masses.
(c) 1990-96 Philip Zimmermann, Phil's Pretty Good Software. 1996-03-04
Uses the RSAREF(tm) Toolkit, which is copyright RSA Data Security, Inc.
Distributed by the Massachusetts Institute of Technology.
Export of this software may be restricted by the U.S. government.
Current time: 1999/04/17 04:23 GMT

Could not read key from file '/root/.pgp/secring.pgp'.
Signature error

For a usage summary, type:  pgp -h
For more detailed help, consult the PGP User's Guide.
make: *** [stamp-buildpackage] Error 20

but when I check, using:

# ls -l /root/.pgp/secring.pgp
-rw-r--r--   1 root     root          588 Apr 16 21:53
/root/.pgp/secring.pgp

so I don't understand why I get "Could not read key from file
'/root/.pgp/secring.pgp'.".  Can anyone provide a clue??  TIA
> 
> On Thu, Apr 15, 1999 at 06:45:40AM -0600, John Galt wrote:
> > Actually, no--there's also a make-kpkg target for module installation,
> > then the .deb kernel image already does the copying and the reinitializing
> > lilo just like the pre-rolled images on ftp.debian.org.  The following
> > steps are make-kpkg modules (IIRC) and dpkg -i <.debfile in /usr/src>.
> 
> "make-kpkg kernel_image" compiles and packages the kernel including
> the modules.
> 
> "make-kpkg modules_image" compiles any ADDITIONAL module sources found
> in /usr/src/modules, such as PCMCIA and ALSA. If you have not installed
> any module source packages, there is no need to run modules_image.
> These modules are placed in separate .deb files.
> 
> Hamish
> --
> Hamish Moffatt VK3TYD.
> CCs of replies from mailing lists are welcome.
> 
> --
> Unsubscribe?  mail -s unsubscribe debian-user-request@lists.debian.org < /dev/null

-- 
-----------------------------------------
Ralph Winslow		      rjw@nac.net
The IQ of the group is that of the member
whose IQ is lowest  divided by the number
of members.


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