case statement question...

[David Oswald <david.oswald@citicorp.com>]

Hello all - I have a KSH script question...

Can someone out there take a look at this script. I want to perform an
operation based on the day of month. but the days (10 - 31) are giving
me a problem. I would really like to keep this a one liner if i can. How
bout anybody out there done something like this ???

Only the line [30-31] is the offending line...


#!/bin/ksh
echo "Enter the date: (ie Nov 04)"
   read Month Day
   case $Day in
        1 | 01 ) Day=01; SearchStr="$Month  1";;
        2 | 02 ) Day=02; SearchStr="$Month  2";;
        3 | 03 ) Day=03; SearchStr="$Month  3";;
        4 | 04 ) Day=04; SearchStr="$Month  4";;
        5 | 05 ) Day=05; SearchStr="$Month  5";;
        6 | 06 ) Day=06; SearchStr="$Month  6";;
        7 | 07 ) Day=07; SearchStr="$Month  7";;
        8 | 08 ) Day=08; SearchStr="$Month  8";;
        9 | 09 ) Day=09; SearchStr="$Month  9";;
	[30-31]) SearchStr="$Month $Day";;
        *) ERROR;; # call error routine
   esac

echo $SearchStr

i guess i could use the following statements below but I want to know if
I can use a 10-31 as a qualifier...

#       [12][0-9]) SearchStr="$Month $Day";;
#	30 | 31 ) Day=02; SearchStr="$Month  9";;


thanks in advance ...


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