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Re: bash; nur eine variablen zuweisung



Hi,

* Roland M. Kruggel wrote (2006-11-27 15:41):
>...und nun sind meine ganzen lienefeeds weg.
>-->
>mail1:~# a=`tail -4 /var/log/auth.log`
>mail1:~# echo $a
>Nov 27 15:35:01 mail1 sshd[15593]: (pam_unix) session opened for user 
>rkruggel by (uid=0) Nov 27 15:35:31 mail1 sshd[15593]: (pam_unix) 
>session closed for user rkruggel Nov 27 15:35:52 mail1 sshd[15612]: 
>Accepted publickey for root from 80.145.46.85 port 62875 ssh2 Nov 27 
>15:35:52 mail1 sshd[15627]: (pam_unix) session opened for user root 
>by root(uid=0)
>--<
>
>Wie krieg ich meine linefeeds wieder hin?

Gute Frage, bei mir sind die Linefeeds da, wo sie hingehören.

Was ist das Ergebnis von
    foo=`tail -4 /var/log/auth.log`
    echo $foo >foo.out
    cat foo.out

Was sagt 'echo $IFS'?

Hast Du es mit $() versucht?


Thorsten
-- 
If I have seen further, it is by standing on the shoulders of giants.
    - Sir Isaac Newton

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