Bug#811591: FTBFS with GCC 6: statement indented as if it were guarded by
Package: ifhp
Version: 3.5.20-13
Severity: important
User: debian-gcc@lists.debian.org
Usertags: ftbfs-gcc-6 gcc-6-misleading-indentation
This package fails to build with GCC 6. GCC 6 has not been released
yet, but it's expected that GCC 6 will become the default compiler for
stretch.
Note that only the first error is reported; there might be more. You
can find a snapshot of GCC 6 in experimental. To build with GCC 6,
you can set CC=gcc-6 CXX=g++-6 explicitly.
> sbuild (Debian sbuild) 0.67.0 (26 Dec 2015) on dl580gen9-02.hlinux
...
> make[2]: Entering directory '/<<PKGBUILDDIR>>/src'
> gcc -g -W -Wall -Werror -Wno-unused -g -Wno-unused-parameter -g -W -Wall -Werror -Wno-unused -DHAVE_CONFIG_H -I. -I.. -I. -DIFHP_CONF=\"/etc/ifhp.conf\" -DLOCALEDIR=\"/usr/share/locale\" -c -o ifhp.o ifhp.c
> ifhp.c: In function 'Process_job':
> ifhp.c:1348:35: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( tempfd > 0 ) close(tempfd); tempfd = -1;
> ^~~~~~
>
> ifhp.c:1348:3: note: ...this 'if' clause, but it is not
> if( tempfd > 0 ) close(tempfd); tempfd = -1;
> ^~
>
> ifhp.c: In function 'Pjl_setvar':
> ifhp.c:3382:36: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( working ) free( working ); working = 0;
> ^~~~~~~
>
> ifhp.c:3382:5: note: ...this 'if' clause, but it is not
> if( working ) free( working ); working = 0;
> ^~
>
> ifhp.c: In function 'Do_sync':
> ifhp.c:3677:35: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( use_prog ) free( use_prog ); use_prog = 0;
> ^~~~~~~~
>
> ifhp.c:3677:2: note: ...this 'if' clause, but it is not
> if( use_prog ) free( use_prog ); use_prog = 0;
> ^~
>
> ifhp.c: In function 'Do_waitend':
> ifhp.c:4003:35: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( use_prog ) free( use_prog ); use_prog = 0;
> ^~~~~~~~
>
> ifhp.c:4003:2: note: ...this 'if' clause, but it is not
> if( use_prog ) free( use_prog ); use_prog = 0;
> ^~
>
> ifhp.c: In function 'Send_job':
> ifhp.c:4657:36: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( tempfd != 0 ) close(tempfd); tempfd = -1;
> ^~~~~~
>
> ifhp.c:4657:3: note: ...this 'if' clause, but it is not
> if( tempfd != 0 ) close(tempfd); tempfd = -1;
> ^~
>
> ifhp.c: In function 'Make_stdin_file':
> ifhp.c:5098:28: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( fd != 0 ) close(fd); fd = -1;
> ^~
>
> ifhp.c:5098:3: note: ...this 'if' clause, but it is not
> if( fd != 0 ) close(fd); fd = -1;
> ^~
>
> ifhp.c: In function 'Select_model_info':
> ifhp.c:5764:31: error: statement is indented as if it were guarded by... [-Werror=misleading-indentation]
> if( hash ) FREE_OBJ( hash ); hash = 0;
> ^~~~
>
> ifhp.c:5764:2: note: ...this 'if' clause, but it is not
> if( hash ) FREE_OBJ( hash ); hash = 0;
> ^~
>
> cc1: all warnings being treated as errors
> <builtin>: recipe for target 'ifhp.o' failed
--
Martin Michlmayr
Linux for HPE Helion, Hewlett Packard Enterprise
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