In <[🔎] 200906171751.13989.v13@v13.gr>, Stefanos Harhalakis wrote:
>On Wednesday 17 June 2009, Eduardo M KALINOWSKI wrote:
>> On Ter, 16 Jun 2009, Stefanos Harhalakis wrote:
>> > [snip]
>> > Of course you need to look at the C spec to
>> > claim that you understand C in depth (you did... didn't you?) and in
>> > order to understand why
>> >
>> > int n=1; int main() { n=n; printf("%d", n); }
>> >
>> > will not output '1'
>> I couldn't figure why it wouldn't output 1, so I tried (with gcc
>> 4.2.3) and it did print "1".
>>
>> So I'm still curious why you say it would not work.
>There was a typo. Instead of:
>int n=1; int main() { n=n; printf("%d", n); }
>it should be:
>int n=1; int main() { int n=n; printf("%d", n); }
>
>Hope this clears things.
Yeah, and I don't think you *have* to read the C standard to understand why
this doesn't work. Scoping rules are often covered in quick-start guides,
and they would include the statement that 'a local variable's scope begins
at the *start* of it's declaration and ends at the end of the containing
block' with the specific admonition that 'int n = n;' "initializes" n to
whatever value was at that location before n was initialized, leaving n with
an unknown, not well-defined value.
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