Bug#663351: lsb-base: pidofproc() declares unused local variable and use undeclared variable

[Liu Yubao <yubao.liu@gmail.com>]

Package: lsb-base
Version: 3.2+Debian29
Severity: minor

Dear Maintainer,

I find there is a minor issue in pidofproc() function.

/lib/lsb/init-functions:
> pidofproc () {
>     local pidfile line status specified pid
                    ~~~~ I guess "line" should be "base".

>     pidfile=
>     specified=
>
>     OPTIND=1
>     while getopts p: opt ; do
>         case "$opt" in
>             p)  pidfile="$OPTARG"
>                 specified="specified"
>                 ;;
>         esac
>     done
>     shift $(($OPTIND - 1))
>
>     base=${1##*/}
      ~~~~~~~~~~~~~ this is will change a global variable "$base".

>     if [ ! "$specified" ]; then
>         pidfile="/var/run/$base.pid"
>     fi

Regards,
Yubao Liu

-- System Information:
Debian Release: wheezy/sid
  APT prefers unstable
  APT policy: (500, 'unstable')
Architecture: i386 (i686)

Kernel: Linux 3.1.0-1-686-pae (SMP w/1 CPU core)
Locale: LANG=en_US.UTF-8, LC_CTYPE=zh_CN.UTF-8 (charmap=UTF-8)
Shell: /bin/sh linked to /bin/dash

Versions of packages lsb-base depends on:
ii  ncurses-bin  5.9-4
ii  sed          4.2.1-9

lsb-base recommends no packages.

lsb-base suggests no packages.

-- no debconf information