Re: Kernel-package, fix version 2 ...

[Sven Luther <sven.luther@wanadoo.fr>]

On Sun, Oct 23, 2005 at 10:49:18AM +0200, Erik van Konijnenburg wrote:
> On Sun, Oct 23, 2005 at 08:08:50AM +0200, Sven Luther wrote:
> > On Sun, Oct 23, 2005 at 03:00:12AM +0200, Jonas Smedegaard wrote:
> > > On Sat, 22 Oct 2005 23:50:10 +0200 Sven Luther <sven.luther@wanadoo.fr> wrote:
> > > >   1) how can i check if there is only one entry in the ramdisk=
> > > > line ? Reading the length of the list, or doing a shift and checking
> > > > for and empty list ? 
> > > 
> > > split it with the delimiting character (I proposed colon - as in
> > > $PATH - but don't know if it makes better sense to use comma or space).
> > > 
> > > 
> > > Here's what you deciphered yourself tonight in yaird, splitting a path
> > > into directoy/file components:
> > > 
> > >   my @components = split (/\/+/, $path);
> > > 
> > > 
> > > If you want _either_ colon, comma or whitespace as delimiter (not sure
> > > that is a good idea though) then something like this should work:
> > > 
> > >   my @entries = split (/[:,\s]+/, $line);
> > 
> > Well, we already do that, in fact :
> > 
> >     (split (/ /, $ramdisk));
> > 
> > But the problem is not how to split it, but how to detect it is of length 1,
> > that is having the legacy single entry in the field.
> 
> Two options:
> 
> a) for array @entries, $#entries will contain index of last element.
>    if that is -1, there were no elements, if 0, there's exactly
>    one, named $entries[0].
> 
> b) if @entries is used in a scalar context, it will be interpreted as
>    number of elements in the array:
> 
>    if (@entries == 1) {print "Just one\n"; }

I implemented something using scalar(@ramdisklist). Works but maybe not as
nice.

BTW, can i do :

  if ((scalar @ramdisklist) == 1) ... 

?

Friendly,

Sven Luther