Bug#478734: g++-4.2: refuses to compile valid C++ syntax

[Jason Kraftcheck <kraftche@cae.wisc.edu>]

The same syntax is accepted by the only other C++ compiler I have access 
too: Sun's.  I guess what I don't understand is why, if I create a 
temporary by explicitly calling the copy constructor, that temporary is 
treated as an rvalue.

So how do you want to proceed?  If you're certain that you're correct 
then I have no objection to you closing the bug report. Please do so 
with my apologies for being a nuisance, as I'm certainly not sure that 
I'm correct.  Or if you prefer, I could post the question to comp.lang.c++.

thanks,

- jason