Inline constant function pointers

[Matthias Klose <doko@net.local>]

>Submitter-Id:	net
>Originator:	Ian Turner <vectro@pipeline.com>
>Organization:	The Debian Project
>Confidential:	no
>Synopsis:	
>Severity:	non-critical
>Priority:	low
>Category:	optimization
>Class:		change-request
>Release:	3.2.1 (Debian) (Debian unstable)
>Environment:
System: Debian GNU/Linux (unstable)
Architecture: i686
host: i386-linux
Configured with: ../src/configure -v --enable-languages=c,c++,java,f77,proto,pascal,objc,ada --prefix=/usr --mandir=/usr/share/man --infodir=/usr/share/info --with-gxx-include-dir=/usr/include/c++/3.2 --enable-shared --with-system-zlib --enable-nls --without-included-gettext --enable-__cxa_atexit --enable-clocale=gnu --enable-java-gc=boehm --enable-objc-gc i386-linux
Thread model: posix
gcc version 3.2.2 20021212 (Debian prerelease)
>Description:
[ Reported to the Debian BTS as report #173513.
  Please CC 173513@bugs.debian.org on replies.
  Log of report can be found at http://bugs.debian.org/173513 ]
	

Currently GCC will not inline a call of a function pointer that is known 
at compile time. For example, the following code will still result in 
the instruction "call funk" when run with -finline-functions on i386:

#include <stdio.h>

static char* funk() {
  return "Hello World.\n";
}

static void funky(char*(*func)()) {
  printf("%s", func());
}

void main() {
  funky(funk);
}

Although the call to funky is inlined, the call to funk is not, because 
in the source code it appears as a call of a function pointer. But as a 
consequence of funky being inlined, it would be possible to inline funk 
as well.
>How-To-Repeat:
	
>Fix: