gcc does not output weak symbol unless declared
>Submitter-Id: net
>Originator: Benoit Poulot-Cazajous
>Organization:
>Confidential: no
>Synopsis: #pragma weak problem
>Severity: serious
>Priority: low
>Category: c
>Class: wrong-code
>Release: 3.1.1 (Debian testing/unstable)
>Environment:
System: Linux walhalla 2.4.19 #2 Sat Aug 3 11:56:01 CEST 2002 i686 unknown unknown GNU/Linux
Architecture: i686
host: i386-pc-linux-gnu
build: i386-pc-linux-gnu
target: i386-pc-linux-gnu
configured with: /mnt/data/gcc-3.1/gcc-3.1-3.1.1ds3/src/configure -v --enable-languages=c,c++,java,f77,proto,objc,ada --prefix=/usr --mandir=/usr/share/man --infodir=/usr/share/info --with-gxx-include-dir=/usr/include/c++/-3.1 --enable-shared --with-system-zlib --enable-long-long --enable-nls --without-included-gettext --enable-clocale=gnu --enable-__cxa_atexit --enable-threads=posix --enable-java-gc=boehm --enable-objc-gc i386-linux
>Description:
When using '#pragma weak bar = foo', gcc does not output anything, unless
bar is declared.
gcc-2.95 and other compilers do not require such a declaration.
>How-To-Repeat:
$ cat bug.c
#pragma weak bar = foo
$ gcc-3.1 bug.c -S -o -
.file "bug.c"
.ident "GCC: (GNU) 3.1.1"
$ gcc-2.95 bug.c -S -o -
.file "bug.c"
.version "01.01"
gcc2_compiled.:
.weak bar
.set bar,foo
.ident "GCC: (GNU) 2.95.4 20011002 (Debian prerelease)"
In order to get the correct output, bar() has to be declared :
$ cat bug2.c
#pragma weak bar = foo
void bar();
$ gcc-3.1 bug2.c -S -o -
.file "bug2.c"
.weak bar <=== Ok !!!
.set bar,foo <===/
.ident "GCC: (GNU) 3.1.1"
>Fix:
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