Re: Bug#119440: g++: Compiler does not give any errors when a function fails to return required value

["Martin v. Loewis" <martin@v.loewis.de>]

> Are there any warnings that are enabled by default?

Yes. For example, compiling

void x(){
	short y = 0xFFFF0000;
}

gives the warning

warning: overflow in implicit constant conversion

However, this is different from the -Wreturn-type warning: The
compiler has reliable algorithm that guarantees that the warning is
only issued whenever the program has undefined behaviour (as it does
when converting a large integer constant to short).

A similar algorithm does not exist for reliably determining that a
function falls off its end.

Regards,
Martin