Re: Introducing security hardening features for Lenny
On Wed, Mar 05, 2008 at 09:55:37AM -0800, Kees Cook wrote:
>>> t.test(x=c(10.87,10.873,10.854,10.809,10.877),y=c(10.807,10.824,10.963,10.84,10.838))
> What tool is this you're using?
GNU R. Takes a while to get into, but hard to beat for statistics.
>> data: c(10.87, 10.873, 10.854, 10.809, 10.877) and c(10.807, 10.824, 10.963, 10.84, 10.838)
>> t = 0.0722, df = 5.561, p-value = 0.945
>> alternative hypothesis: true difference in means is not equal to 0
>> 95 percent confidence interval:
>> -0.07382831 0.07822831
>> sample estimates:
>> mean of x mean of y
>> 10.8566 10.8544
> Which of these outputs should be paid attention to?
The p-value is a good idea. If it's about 0.05, people tend to say the result
is statistically significant. In your case it's 0.945, which means that the
result is for all practical purposes worthless.
/* Steinar */
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Homepage: http://www.sesse.net/
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