On Thu, Sep 26, 2002 at 11:45:40AM +0200, Kurt Bernhard Pruenner wrote: > I guess using ${!foo} would help, which takes the content of the > variable foo and uses that as the variable to get the content from, i.e. > > foo=PATH > echo ${!foo} > > would print your PATH... Beware that that's a bashism. You need eval to do it portably. -- Colin Watson [cjwatson@flatline.org.uk]