On Thu, Sep 26, 2002 at 11:45:40AM +0200, Kurt Bernhard Pruenner wrote:
> I guess using ${!foo} would help, which takes the content of the
> variable foo and uses that as the variable to get the content from, i.e.
>
> foo=PATH
> echo ${!foo}
>
> would print your PATH...
Beware that that's a bashism. You need eval to do it portably.
--
Colin Watson [cjwatson@flatline.org.uk]