On Tue, Jul 10, 2001 at 12:20:49AM +0100, Moof wrote: > But e^(i * pi) is integer, and equal to 1. No, e^(i*pi) is equal to -1, that way you have e^(i*pi) + 1 = 0 an equation linking 1, 0 and three irrational numbers. BTW, I think (e + pi) has not been proven to be irrational, is that so? -- Leo Howell M5AKW freenet:MSK@SSK@2vz8xnhEJyJOlBVNfBEOWaohQFEQAgE/freesite//
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