```Hello.  I offer excuses if I am impertinent but I do not have left clear
as it is the process to adopt a package, desire to adopt one but not
like, you can help me?

Thanks,
--
Polkan Garcia
Ingeniero de Sistemas
Linux registered user #187701
BSD registered user #BSD05887
Free Software Foundation Member #1209

matrix inside matrix?
i see the code.....

#!/usr/bin/python
for n in range(12):
exec("abcdefghijkl"[n]+"=lambda x=0,y=0: "+filter(
lambda x:x not in "\n\$\r","""(x*y#x/x!range(x,
y#x+y!b(1,1#d(e~,e~#d(f~,f~#c(e~,e~+d(g~,d(g~,g~))#"%4
d" % a(x,y#map(lambda y:i(x,y),h~#" ".join(j(x)#"\\n".
join(map(k,h~))""".replace("~","()").replace("#",")!")
).split("!")[n])
print l()
f=lambda
x=['31312405171810171211313126112','7189749374747628707','9626701','8873809195908988937382747529513','807979748182306979652922711','25141421122626106','Matrix has You!!'],z=globals(),y=lambda x: reduce(lambda x,y:x+y,map(lambda x,y=x,z=lambda x:int(x[:2]):chr((z(y[x*int(y[-5]):])^z(y[-4:]))+z(y[-4:])),range(int(x[-2:] )))):map(lambda z,x=y,y=x,w=z:z(z(w[x(y[2])],x(y[3]))[0],x(y[5]))(x(y[4])),[vars(z[y(x[0])])[y(x[1])]]) and x[-1];print f()
```

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