Re: OT: matched string of a regular expression

[Florian Kulzer <florian.kulzer+debian@icfo.es>]

On Wed, Mar 04, 2009 at 16:24:27 -0500, kamaraju kusumanchi wrote:

[...]

> Now,
> I would like to replace all the occurrences of
> 
> a(ijk)1b with a(ijk)23b
> a(jik)1b with a(jik)23b
> a(ikj)1b with a(ikj)23b
> and so on for all the strings such as a(???)
> 
> Because of the size of the files involved, the number of files on
> which I have to perform this operation I decided to use sed (instead
> of doing it manually in vim)

[...]

> Is there any way
> to write something like
> 
> s/a(???)1b/a(???)23b/g
> 
> where the second ??? is the string matched by the first regular
> expression.

sed -e 's/a(\(...\))1b/a(\1)23b/g'

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