On Mon, May 27, 2002 at 10:25:28AM +0800, Squirrel wrote:
where's the question?
oh, it's in the subject. how about putting the message in the
message?
The question was :
What's the meaning of "echo $@"?
To start with, 'echo' is a command. Depending on your shell it is
either built-in or it is /bin/echo (in bash it is built in). It is
explained in the 'echo' manpage (if using /bin/echo) or the 'bash'
manpage (if using bash's built-in echo).
The "$@" part is an argument to echo. Names beginning with $ are
shell variables and are expanded by the shell before the application
sees them. In the bash manpage :
~~~~
Special Parameters
@ Expands to the positional parameters, starting from one.
When the expansion occurs within double quotes, each
parameter expands to a separate word. That is, "$@"
is equivalent to "$1" "$2" ... When there are no
positional parameters, "$@" and $@ expand to nothing
(i.e., they are removed).
~~~~
-D
--
"Don't use C; In my opinion, C is a library programming language
not an app programming language." - Owen Taylor (GTK+ developer)
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