Re: Is it perfectly to pass argv[] this way to function ?

[Michael van der Kolff <vandy@aperfectpc.com>]

On Tuesday 21 May 2002 04:31 am, Deepak Kotian wrote:
> Hi,
>
> Please check the code segment.
> /*************code start ****/
> #include <stdio.h>
> int func1(char **a_argv){
>  while (*a_argv!=NULL)
>  printf("\n%s", *a_argv++);
>  return(0);
> }
>
> int main(int argc, char *argv[]){
>  func1(&argv[0]);
> }
> /*************code end ****/
>
> This func1 function prints all the arguments with no problem, because
> main() is probably always on stack, so it works probably.
> Do anyone see any problem, if one passes argv[] this way ? Will there be
> portability issues, like on other UNIX flavors,etc.
>
> Please let me know.
>
> Thanks and Regards
> Deepak

It might work, but I'd say it's probably more standard and more portable to 
use standard


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