Re: case statement question...

[Ben Pfaff <pfaffben@pilot.msu.edu>]

David Oswald <david.oswald@citicorp.com> writes:

> 
> Hello all - I have a KSH script question...
> 
> Can someone out there take a look at this script. I want to perform an
> operation based on the day of month. but the days (10 - 31) are giving
> me a problem. I would really like to keep this a one liner if i can. How
> bout anybody out there done something like this ???
> 
> Only the line [30-31] is the offending line...
> 
> 
> #!/bin/ksh
> echo "Enter the date: (ie Nov 04)"
>    read Month Day
>    case $Day in
>         1 | 01 ) Day=01; SearchStr="$Month  1";;
>         2 | 02 ) Day=02; SearchStr="$Month  2";;
>         3 | 03 ) Day=03; SearchStr="$Month  3";;
>         4 | 04 ) Day=04; SearchStr="$Month  4";;
>         5 | 05 ) Day=05; SearchStr="$Month  5";;
>         6 | 06 ) Day=06; SearchStr="$Month  6";;
>         7 | 07 ) Day=07; SearchStr="$Month  7";;
>         8 | 08 ) Day=08; SearchStr="$Month  8";;
>         9 | 09 ) Day=09; SearchStr="$Month  9";;

Looking at the above lines, I am thinking that you probably don't want
the semicolons after the Day= instructions.

A simpler way would be something like:

	[1-9]) Day="0$Day" SearchStr="$Month  $Day";;
        0[1-9]) SearchStr="$Month  `echo $Day | sed 's/^0//'`"

> 	[30-31]) SearchStr="$Month $Day";;

If you want to match all the dates 10-31 here, you want the expression
`[12][0-9] | 3[0-1])' instead.

>         *) ERROR;; # call error routine
>    esac
> 
> echo $SearchStr

All of this is untested so it should be taken with quite a tonnage of
salt.
-- 
Ben Pfaff <pfaffben@pilot.msu.edu> <blp@gnu.org> <pfaffben@debian.org>
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