Re: [UDD] Help needed for exit code of udd.py

[Jakub Wilk <jwilk@debian.org>]

* Andreas Tille <andreas@an3as.eu>, 2012-02-19, 12:41:
> --- udd.py      (Revision 2154)
> +++ udd.py      (Arbeitskopie)
> @@ -62,6 +62,7 @@
>         if "update-command" in src_config:
>           result = system(src_config['update-command'])
>           if result != 0:
> +            print "False =", result
>             sys.exit(result)
>         end_time = get_timestamp()
>       else:
>
>
> and tried:
>
> $ udd.py config-org.yaml update bibref && echo test
> False = 2048
> test
>
>
> Could anybody explain why if the python script exits a non-zero value 
> the second part of the statement (&& echo test) is executed?

This is not explicitly documented in Python documentation, but the 
sys.exit() function behaves like the C exit() function with respect to 
exit codes:

“The exit() function causes normal process termination and the value of 
status & 0377 is returned to the parent […].”

2048 & 0377 == 0

You probably want to replace "sys.exit(result)" with "sys.exit(1)".

--
Jakub Wilk