Re: Kernel-package, fix version 2 ...
On Sun, Oct 23, 2005 at 08:08:50AM +0200, Sven Luther wrote:
> On Sun, Oct 23, 2005 at 03:00:12AM +0200, Jonas Smedegaard wrote:
> > On Sat, 22 Oct 2005 23:50:10 +0200 Sven Luther <sven.luther@wanadoo.fr> wrote:
> > > 1) how can i check if there is only one entry in the ramdisk=
> > > line ? Reading the length of the list, or doing a shift and checking
> > > for and empty list ?
> >
> > split it with the delimiting character (I proposed colon - as in
> > $PATH - but don't know if it makes better sense to use comma or space).
> >
> >
> > Here's what you deciphered yourself tonight in yaird, splitting a path
> > into directoy/file components:
> >
> > my @components = split (/\/+/, $path);
> >
> >
> > If you want _either_ colon, comma or whitespace as delimiter (not sure
> > that is a good idea though) then something like this should work:
> >
> > my @entries = split (/[:,\s]+/, $line);
>
> Well, we already do that, in fact :
>
> (split (/ /, $ramdisk));
>
> But the problem is not how to split it, but how to detect it is of length 1,
> that is having the legacy single entry in the field.
Two options:
a) for array @entries, $#entries will contain index of last element.
if that is -1, there were no elements, if 0, there's exactly
one, named $entries[0].
b) if @entries is used in a scalar context, it will be interpreted as
number of elements in the array:
if (@entries == 1) {print "Just one\n"; }
Regards,
Erik
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