On Sun, 2002-12-15 at 14:46, Raul Miller wrote:
> Under 5.2 Appointment of project leader, change item 7 to read:
>
> 7. The decision will be made using A.6 of the Standard Resolution
Insert "section" between "using" and "A.6"
> Procedure. The quorum is the same as for a General Resolution
> (s.4.2) except the default option is None Of The Above.
I assume the "s" is supposed to be ISO-8859-1 character code 167, the
section symbol, "§"?
>
> 7. Appoint the Chairman of the Technical Committee. The Chairman
> is elected by the Committee from its members. All members of the
> committee are automatically nominated; the committee vote starting
Change "vote" after "committee" to "votes". Alternatively, if "committee
vote" is the name or description of the event, then change "starting" to
"starts".
The third, and my favorite, alternative is "the committee starts voting"
> one week before the post will become vacant (or immediately, if it
> is already too late). The members may vote by public acclamation
> for any fellow committee member, including themselves; there is
Either the "all members of the committee are automatically nominated" or
the "for any fellow committee member, including themselves" is
redundant.
> no default option. The vote finishes when all the members have
> voted or when the outcome is no longer in doubt. The result is
Here you use the short form "no longer in doubt". However, above (not
quoted, in 4.2.3) you did a long-run around this phrase. I suggest just
using the phrase, and finding somewhere to define it.
> Replace A.3 with:
>
> A.3. Voting procedure
>
> 1. Each independent set of related amendments is voted on in a
> separate ballot. Each such ballot has as options all the sensible
> combinations of amendments and options from that set, and a default
Strike "such" in "Each such ballot." Further, there is something wrong
there --- I think the second use of options ("amendments and options")
should be struck.
> option. If the default option wins then the entire resolution
> procedure is set back to the start of the discussion period.
> 4. Votes may be cast during the voting period, as specified elsewhere.
> If the voting period can end if the outcome is no longer in
> doubt, the possibility that voters may change their votes is
> not considered.
Strike "if" in "if the voting...."
Change "in doubt, the" to "in doubt, ignoring the" and strike "is not
considered" from the end. Alternatively, if you like the phrase "not
considered," then use "not considering" instead of "ignoring"
> Replace A.5 with:
>
> A.5. Expiry
>
> If a proposed resolution has not been discussed, amended, voted on or
> otherwise dealt with for 4 weeks the secretary may issue a statement
change "4" to "four"
> that the issue is being withdrawn. If none of the sponsors of any
> of the proposals object within a week, the issue is withdrawn.
Change "any of the proposals" to "the proposal". We are talking about a
single "proposed resolution". If this was intended to allow sponsors of
amendments to object, then that needs to be clarified (e.g., "of the
proposal or any amendments of it")
>
> The secretary may also include suggestions on how to proceed,
> if appropriate.
I don't think that sentence is needed.
> A.6 Vote Counting
>
> 1. Each voter's ballot ranks the options being voted on. Not all
> options need be ranked. Ranked options are considered preferred
> to all unranked options. Voters may rank options equally.
> Unranked options are considered to be ranked equally with one
> another, and below any explicitly ranked options. The other
> details of how ballots may be filled out will be included in
> the Call For Votes.
Change "may" to "must" in "may be filled." The act of voting itself is
optional, however, the format of the ballot is not.
Also, "filled in" seems to be slightly preferred over "filled out",
according to Google.
> 2. If the ballot has a quorum requirement (Q) any options other
> than the default option which do not receive at least Q votes
> ranking that option above the default option are dropped from
> consideration.
Q is not the number of votes needed for the quorum! Sometimes, quorum is
2. Other times it is thrice Q --- that is, 3Q.
Q is just a number defined in 4.2.7 as half the square root of the
number of developers.
> 3. Any option which does not defeat the default option by its
> required majority ratio is dropped from consideration.
> a. An option A defeats an option B if N(A,B)*V(A,B) is larger
> than N(B,A)*V(B,A) and if the (A,B) defeat has not been
> dropped.
I was about to tell you to define A, B, N, V, and (A,B) but I see you've
done it below. Please make this (c) --- put the definitions above their
use.
> b. Given two options A and B, V(A,B) is the number of voters
> who prefer option A over option B.
> c. If a majority of n:1 is required for A, and B is the default
> option, N(B,A) is n. In all other cases, N(B,A) is 1.
Erm, we use N(A,B) above, but define N(B,A) here.
> 4. We construct the Schwartz set based on undropped options and
> defeats:
> a. An option A is in the Schwartz set if for all options B,
> either A transitively defeats B, or B does not transitively
> defeat A.
> b. An option A transitively defeats an option C if A defeats
> C or if there is some other option B where A defeats B
> AND B transitively defeats C.
Once again, change (a) and (b).
> 5. If there are defeats between options in the Schwartz set, we
> drop the weakest such defeats, and return to step 4.
> a. A defeat (A,X) is weaker than a defeat (B,Y) if V(A,X)
> is less than V(B,Y). Also, (A,X) is weaker than (B,Y)
> if V(A,X) is equal to V(B,Y) and V(X,A) is greater than
> V(Y,B).
> b. A weakest defeat is a defeat that has no other defeat
> weaker than it. There may be more than one such defeat.
Well, you can guess what I'm going to say here.
> 6. If there are no defeats within the Schwartz set, then the winner
> is chosen from the options in the Schwartz set. If there is
> only one such option, it is the winner. If there are multiple
> options, the elector with a casting vote chooses which of those
> options wins. If there are no options in the Schwartz set,
> the default option wins.
Is it possible for the default option to be a member of the Schwartz
set? If so, should it win in that case?
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