[Date Prev][Date Next] [Thread Prev][Thread Next] [Date Index] [Thread Index]

Re: OT: matched string of a regular expression



Florian Kulzer wrote:

> On Wed, Mar 04, 2009 at 16:24:27 -0500, kamaraju kusumanchi wrote:
> 
> [...]
> 
>> Now,
>> I would like to replace all the occurrences of
>> 
>> a(ijk)1b with a(ijk)23b
>> a(jik)1b with a(jik)23b
>> a(ikj)1b with a(ikj)23b
>> and so on for all the strings such as a(???)
>> 
>> Because of the size of the files involved, the number of files on
>> which I have to perform this operation I decided to use sed (instead
>> of doing it manually in vim)
> 
> [...]
> 
>> Is there any way
>> to write something like
>> 
>> s/a(???)1b/a(???)23b/g
>> 
>> where the second ??? is the string matched by the first regular
>> expression.
> 
> sed -e 's/a(\(...\))1b/a(\1)23b/g'
> 

You hit it right on the head. The \1 construct is exactly what I am after.
Thanks!

BTW, If anyone is interested, I found this great book called sed & awk (2nd
Edition), by Dale Dougherty, Arnold Robbins
http://www.amazon.com/sed-awk-2nd-Dale-Dougherty/dp/1565922255/ . It's so
far the best documentation I read on sed, awk. It also has lots of
practical tips.

raju
-- 
Kamaraju S Kusumanchi
http://malayamaarutham.blogspot.com/


Reply to: