Paul Johnson wrote:
William Ballard <nospam_40811@alltel.net> writes:On Fri, Sep 24, 2004 at 07:28:22AM -0700, Zachary Rizer wrote:No. Unstable (sid) will always be unstable. Testing becomes the new stable, and then a new testing is born (etch?).Could you be more precise? What is renamed, what is forked, what is cloned?Start of the cycle: Unstable forks a new testing. Testing freezes, frozen replaces testing. Frozen then replaces existing stable, which moves to the obsolete archive.
The 'new' testing will be a fork of stable[which in turn is derived from the 'old' testing], not unstable...
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