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Re: Frage: Kommt nach 'woody' 'sid'???



On Wed, 05 Jun 2002, Peter Palfrader wrote:

> $FRUEHER:
>  stable    -> hamm
>  unstable  -> potato
>   (sid war experimental)
> 
> dann freeze von potato:
>  stable    -> hamm
>  frozen    -> potato
>  unstable  -> woody
>   (sid war experimental)
> 
> release
>  stable    -> potato
>  unstable  -> woody
>   (sid war experimental)
> 
> package pools - Present day:
>  stable    -> potato
>  testing   -> woody
>  unstable  -> sid
>   (experimental hat keinen schoenen Namen mehr)

wenn woody stable wird:
 package pools - Present day:
  stable    -> woody
  testing   -> sgelse
  unstable  -> sid
   (experimental hat keinen schoenen Namen mehr)



nur der Vollstaendigkeit halber
					yours,
					peter

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