On Thu, Oct 13, 2005 at 08:18:05AM -0700, Freddy Freeloader wrote:
> b=${a/23/BB}
>
> echo "b = $b"
>
> Now the ABS guide says that where I'm setting b it should be
> substituting BB for 23. It also says that the output of 'echo "b - $b"'
> should be: b = BB35
Well, it's taking whatever the value of $a is, and replacing
23 with BB. You didn't specify the value of $a before you
run that substitution; what is it?
--
Stephen R. Laniel
steve@laniels.org
+(617) 308-5571
http://laniels.org/
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