Re: GCC/G++ will not compile i686 binaries when asked.
For the past few weeks I have been co-working on a private project. I
have done allot of work on it and I would hate to have to start over.
The makefile I created for this project explicitly tells the compiler
(g++) to compile the binary using i686 (-march=pentiumpro) assembly
instructions and internal timeings. Yet for some [explitive]
[explitive] reason it refuses to do so and both ?file? amd ?readelf?
tell me it always compiles for a bare i386 despite my explicit
Why the [explitive] does this [explitive] thing not compile the end
result into a i686 only binary as I asked it to?
How the [explitive] do I fix it?
I have read the gcc/g++ manual pages. I have googled. I have spent
the past hour dedicating myself to this problem, and nothing seems to
This is [b]really[/b] getting to me. Please help.
I'm curious about why it's particularly important to you?
For sure gcc will do what you want: I have been caught booting a kernel
that trapped on a Pentium because it was built for 686, and when I
redeployed a Pentium II (it was running RHL 7.3) I replaced the kernel
and (I think glibc) but got caught on the ssl libraries - it's a mazing
how many programs won't run with broken openssl!.
So the Q is, how do you know it's not working for you?
Have you tried building for an Athlon and running on your target?
Do you have a small test program that illustrates your problem? If you
come up with (say) ten lines of C, probablly people here will check it
out for you on a variety of software.
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